Answer
(a) $5.1s$
(b) $8.3m$
Work Step by Step
(a) We can find the required time as
$t=\frac{v-v_{\circ}}{a}$
We plug in the known values to obtain:
$t=\frac{0-3.25m/s}{-0.6375m/s}$
$t=5.1s$
(b) The required distance can be determined as
$x=v_{\circ}t+\frac{1}{2}at^2$
We plug in the known values to obtain:
$x=(3.25)(5.098)+\frac{1}{2}(-0.63756)(5.098)^2$
$x=16.5685-8.2850$
$x=8.3m$
