Answer
(a) $0.24KN$
(b) increase
Work Step by Step
(a) we know that
$F=mgsin\theta$
We plug in the known values to obtain:
$F=(65)(9.8)sin22^{\circ}$
$F=238.62N$
$F=0.238KN=0.24KN$
The direction of the force is parallel to the incline.
(b) Since $F=mgsin\theta$, this equation shows that the net force is directly proportional to $sin\theta$. Thus, when the slope becomes steeper, $sin\theta$ will increase and as a result the net force on the skier will also increase.
