Answer
(a) $n=12$
(b) $7.62nm$
Work Step by Step
(a) We know that
$n=\frac{\lambda_n}{2\pi r_1}$
We plug in the known values to obtain:
$n=\frac{3.99\times 10^{-9}}{(2)(3.14)(5.29\times 10^{-11})}$
$n=12$
(b) The Bohr radius is given as
$r_n=n^2\times r_1$
We plug in the known values to obtain:
$v_n=(12^2)(5.29\times 10^{-11}m)$
$v_n=7.62nm$