Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1115: 93

Answer

(a) $n=12$ (b) $7.62nm$

Work Step by Step

(a) We know that $n=\frac{\lambda_n}{2\pi r_1}$ We plug in the known values to obtain: $n=\frac{3.99\times 10^{-9}}{(2)(3.14)(5.29\times 10^{-11})}$ $n=12$ (b) The Bohr radius is given as $r_n=n^2\times r_1$ We plug in the known values to obtain: $v_n=(12^2)(5.29\times 10^{-11}m)$ $v_n=7.62nm$
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