Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1115: 87

Answer

$T=n^3T_1$ $n=1,2,3,....$ where $T_1=\frac{h^3}{4\pi^2mk^2e^4}$

Work Step by Step

We know that $T=\frac{2\pi r_n}{v_n}$ but $r_n=\frac{n^2h^2}{4\pi^2mke^2}$ and $v_n=\frac{2\pi ke^2}{nh}$ Now $T=\frac{2\pi(\frac{n^2h^2}{4\pi^2mke^2})}{\frac{2\pi ke^2}{nh}}$ This simplifies to: $T=n^3(\frac{h^3}{4\pi^2mk^2e^4})$ $T=n^3T_1$ $n=1,2,3,....$ where $T_1=\frac{h^3}{4\pi^2mk^2e^4}$
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