Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1112: 16

Answer

$8.22\times 10^{-8}N$

Work Step by Step

We know that $F=\frac{Ke^2}{r^2}$ We plug in the known values to obtain: $F=\frac{(8.99\times 10^9)(1.60\times 10^{-19})^2}{(5.29\times 10^{-11})^2}$ $F=8.22\times 10^{-8}N$
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