Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1112: 15

Answer

$2.42\times 10^{-3}$

Work Step by Step

We can find the ratio $\frac{v}{c}$ as follows: $\frac{v}{c}=\frac{2\pi Ke^2}{nhc}$ We plug in the known values to obtain: $\frac{v}{c}=\frac{2\pi(8.99\times 10^9)(1.60\times 10^{-19})^2}{2(3.00\times 10^8)(6.63\times 10^{-34})}$ $\frac{v}{c}=2.42\times 10^{-3}$
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