Answer
a) First station
b) Second station
Work Step by Step
(a) We are given the power of both stations and we can express power as:
$P=nhf$, where $n$ is the number of photons emitted per second and $f$ is the frequency.
The power is the same, so:
$n_1f_1=n_2f_2$
$\implies \frac{n_1}{n_2}=\frac{f_2}{f_1}$
This equation shows us that frequency and the number of photons emitted per second are inversely proportional. Thus, the first station with a smaller frequency emits more photons per second.
(b) We know that
$E=hf$
This shows us that frequency is directly proportional to energy. Hence the second station with a higher frequency has more energy than the first one.
