Answer
$6.41\times 10^{-19}J$
Work Step by Step
We know that
$W_{\circ}=hf-K_{max}$
We plug in the known values to obtain:
$W_{\circ}=(6.63\times 10^{-34}J.s)(9.95\times 10^{14}Hz)-0.180\times 10^{-19}J$
$W_{\circ}=6.41\times 10^{-19}J$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1074: 20
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