Answer
$0.312c$
Work Step by Step
We know that
$\frac{1}{2}mv^2=eV$
This simplifies to:
$v=\sqrt{\frac{2eV}{m}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{2(1.60\times 10^{-19})(25.0\times 10^3)}{9.11\times 10^{-31}}}$
$v=9.37\times 10^7m/s$
$v=\frac{9.37\times 10^7}{3.00\times 10^8}=0.312c$
