Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1045: 104

Answer

(a) $-0.956c$ (b) $-0.371c$

Work Step by Step

(a) We know that $v_{21}=-\frac{v_{23}-v_{13}}{1-\frac{v_{23}v_{13}}{c^2}}$ We plug in the known values to obtain: $v_{21}=-\frac{0.371c+0.906c}{1+(0.371)(0.906)}$ $v_{21}=-0.956c$ (b) We know that $v_{23}=\frac{v_{21}+v_{13}}{1+\frac{v_{21}v_{13}}{c^2}}$ We plug in the known values to obtain: $v_{23}=\frac{-0.906c+0.806c}{1+\frac{(-0.906c)(0.806c)}{c^2}}$ $\implies v_{23}=-0.371c$
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