Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1004: 13

Answer

(a) increase (b) $\Delta l=m\lambda $

Work Step by Step

(a) We now that $\Delta l=dsin\theta $ This equation shows that the path difference is directly proportional to the angle. Thus, the path difference increases when we move from a bright fringe to the next bright fringe. (b) We know that $\Delta l=dsin\theta $ and $ dsin\theta=m\lambda $ $\implies \Delta l=m\lambda $
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