Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1004: 18

Answer

$92$

Work Step by Step

We know that $dsin\theta=(m-\frac{1}{2})\lambda$ We plug in the known values to obtain: $dsin(0.31^{\circ})=(1-\frac{1}{2})\lambda$ This can be rearranged as: $\frac{d}{\lambda}=\frac{0.5}{sin(0.31^{\circ})}$ $\frac{d}{\lambda}=92$
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