Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 975: 110

Answer

a) $\lt 323cm$ b) $303cm$

Work Step by Step

(a) We know that $\frac{1}{f}=\frac{1}{d_{\circ}}+\frac{1}{d_i}$ $\implies \frac{1}{-301cm}=\frac{1}{\infty}+\frac{1}{d_i}$ $\implies d_i=-301cm$ If the lens in a pair of glasses is $2.00cm$ in front of the person's eye, then the far distance of the person is $d_i=d_{far}-2.00cm$ $\implies 301cm=d_{far}-2.00cm$ $\implies d_{far}=301cm+2.0cm=303cm\lt 323cm$ (b) We have calculated the far point for the person in part(a), which is $303cm$.
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