Answer
Positive
Work Step by Step
We know that
$\frac{1}{f}=\frac{1}{d_{\circ}}+\frac{1}{d_i}$
$\implies \frac{1}{f}=\frac{1}{d_{\circ}}+\frac{1}{-\infty}$
$\implies \frac{1}{f}=\frac{1}{d_{\circ}}$
$\implies P=+\frac{1}{d_{\circ}}$
Thus, the correcting contact lens should be converging and it has a positive refractive power.
