Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 973: 92

Answer

(a) nearsightedness (b) $74.1cm$

Work Step by Step

(a) We know that the negative sign of the power of the lens shows that the lens is a diverging lens. The diverging lens is used to clear off the nearsightedness. The person suffering from the nearsightedness cannot see at the infinite distance or beyond the far point. Thus, the person has nearsightedness. (b) We know that $f_{m}=\frac{1}{P(diopters)}$ $f_{m}=\frac{1}{-1.35diopters}$ $\implies f_{m}=-74.1cm$ Now $q=\frac{1}{\frac{1}{f}-\frac{1}{p}}$ We plug in the known values to obtain: $q=\frac{1}{\frac{1}{-74.1cm}-\frac{1}{\infty}}$ $\implies q=74.1cm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.