Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 904: 85

Answer

$2.00\times 10^{-11}m$

Work Step by Step

We can find the required wavelength as follows: $\lambda=\frac{c}{f}$ We plug in the known values to obtain: $\lambda=\frac{3\times 10^8m/s}{1.50\times 10^{19}Hz}$ $\lambda=2.00\times 10^{-11}m$
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