Answer
$E_{rms}=614\frac{V}{m}$
$B_{rms}=2.05\mu T$
Work Step by Step
We know that
$E_{rms}=\sqrt{\frac{I_{avg}}{c}}$
We plug in the known values to obtain:
$E_{rms}=\sqrt{\frac{1.00\times 10^3}{(3.00\times 10^8)(8.85\times 10^{-12})}}$
$E_{rms}=614\frac{V}{m}$
Similarly $B_{rms}=\frac{E_{rms}}{c}$
$B_{rms}=\frac{614}{3.00\times 10^8}=2.05\mu T$
