Answer
(a) $4.52\times 10^7\frac{C}{Kg}$
(b) less than
Work Step by Step
(a) We know that
$r=\frac{mv}{qB}$
This can be rearranged as:
$\frac{q}{m}=\frac{v}{Br}$
We plug in the known values to obtain:
$\frac{q}{m}=\frac{8.70\times 10^6}{1.21(0.15)}$
$\frac{q}{m}=4.52\times 10^7\frac{C}{Kg}$
(b) As we can see in part (a), $\frac{q}{m}$ is inversely proportional to r. Increasing $r$ thus decreases the $q/m$ ratio.
