Answer
(a) $9.08\times 10^{-12}N$
(b) increase
(c) $14.3\times 10^{-12}N$
Work Step by Step
(a) We know that
$F=B\sqrt{\frac{2e^3V}{m}}$
We plug in the known values to obtain:
$F=(0.957T)\sqrt{\frac{2(1.6\times 10^{-19}C)^3(10.0\times 10^3V)}{9.11\times 10^{-31}Kg}}$
$F=9.08\times 10^{-12}N$
(b) We know that
$F=B\sqrt{\frac{2e^3V}{m}}$
This equation shows that force is directly proportional to voltage. Thus, if voltage is increased then the maximum force in part (a) will also increase.
(c) We know that
$F=B\sqrt{\frac{2e^3V}{m}}$
We plug in the known values to obtain:
$F=(0.957T)\sqrt{\frac{2(1.6\times 10^{-19}C)^3(25.0\times 10^3V)}{9.11\times 10^{-31}Kg}}$
$F=14.3\times 10^{-12}N$
