Answer
$6.25\times 10^4\frac{electrons}{s}$
Work Step by Step
As we know that
$\frac{\Delta N}{\Delta t}=\frac{I}{e}$
We plug in the known values to obtain:
$\frac{\Delta N}{\Delta I}=\frac{10\times 10^{-15}}{1.6\times 10^{-19}}$
$\frac{N}{\Delta t}=6.25\times 10^4\frac{electrons}{s}$
