Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 754: 2

Answer

$\Delta Q=14.04C$ $n=8.755\times 10^{19}electrons$

Work Step by Step

We can find the required charge as $\Delta Q=I\Delta t$ We plug in the known values to obtain: $\Delta Q=0.18\times 78$ $\Delta Q=14.04C$ Now we can find the number of electrons $n=\frac{\Delta Q}{e}$ We plug in the known values to obtain: $n=\frac{14.04}{1.6\times 10^{-19}}$ $n=8.755\times 10^{19}electrons$
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