Answer
$\Delta Q=14.04C$
$n=8.755\times 10^{19}electrons$
Work Step by Step
We can find the required charge as
$\Delta Q=I\Delta t$
We plug in the known values to obtain:
$\Delta Q=0.18\times 78$
$\Delta Q=14.04C$
Now we can find the number of electrons
$n=\frac{\Delta Q}{e}$
We plug in the known values to obtain:
$n=\frac{14.04}{1.6\times 10^{-19}}$
$n=8.755\times 10^{19}electrons$