Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 686: 64

Answer

$0.23KN.\frac{m^2}{C}$

Work Step by Step

We know that $\phi=EAcos\theta$ We plug in the known values to obtain: $\phi=(25,000)(0.0153)cos53^{\circ}$ $\phi=230=0.23KN.\frac{m^2}{C}$
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