Answer
(a) the same as
(b) II
Work Step by Step
(a) We are given that the surface 1 has twice the area of the Gaussian surface 2. According to Gauss's law, the electric flux through the surface is equal to $\frac{1}{\epsilon_{\circ}}$ times the charge (Q) enclosed within the surface. Thus, the flux depends on the charge enclosed in the given area. In the given scenario, the two areas enclose the same charge (Q) and hence the electric flux is the same for both Gaussian surfaces.
(b) We know that the best explanation is option (II) -- that is, the two surfaces enclose the same charge, and hence they have the same electric flux.
