Answer
$4.7\times 10^{-10}m$
Work Step by Step
We know that
$r=\frac{Ke^2}{2K.E}$
We plug in the known values to obtain:
$r=\frac{(8.99\times 10^9)(1.6\times 10^{-19})^2}{2(1.51)(1.6\times 10^{-19})}$
$r=4.7\times 10^{-10}m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 684: 28
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