Answer
a) $F=1.93N$
b) The same force is experienced by the positive and negative charge.
Work Step by Step
(a) We can find the magnitude of the electrostatic force as follows:
$F=K\frac{q_1q_2}{r^2}$
We plug in the known values to obtain:
$F=(8.99\times 10^9)\times \frac{(3.13\times 10^{-6})(4.47\times 10^{-6})}{0.225}$
$F=1.93N$
(b) We know that the magnitude of the force depends on the product of the charges. Thus, the same force is experienced by the positive and negative charge.
