Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 644: 10

Answer

$Q=5.9KJ$

Work Step by Step

We know that $Q=W+\Delta U$ $\implies Q=W+\frac{3}{2}nR(\Delta T)$ We plug in the known values to obtain: $Q=-560+\frac{3}{2}(4)(8.31)(130)$ $Q=5.9KJ$
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