Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 644: 21

Answer

(a) $332K$ (b) $555KJ$

Work Step by Step

(a) We know that $PV=nRT$ This can be rearranged as: $T=\frac{PV}{nR}$ As the process is isothermal so $T_i=T_f=T$ We plug in the known values to obtain: $T=\frac{100\times 10^3(4.00)}{145(8.31)}$ $T=332K$ (b) As $W=nRT\ln(\frac{V_f}{V_i})$ $\implies W=P_iV_i\ln(\frac{V_f}{V_i})$ We plug in the known values to obtain: $W=400(1.00)(\frac{4.00}{1.00})=555KJ$
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