Answer
(a) $4.6MJ$
(b) $2.5Km/s$
Work Step by Step
(a) The required amount of heat can be determined as
$Q=m[c_{steam}\Delta T+L_v+c_w\Delta T^{\prime}+L_f]$
We plug in the known values to obtain:
$Q=(1.5Kg)[(2010J/Kg.K)(110^{\circ}C-100^{\circ}C)+22.6\times 10^5J/Kg+(4186J/Kg.K)(100C^{\circ}-0C^{\circ})+33.5\times 10^4J/Kg]$
$Q=4.6\times 10^6J=4.6MJ$
(b) We can find the required speed as follows:
$Q=\frac{1}{2}mv^2$
This simplifies to:
$Q=\sqrt{\frac{2Q}{m}}$
We plug in the known values to obtain:
$Q=\sqrt{\frac{2(4.55\times 10^6J)}{1.5Kg}}$
$Q=2.5Km/s$
