Answer
(a) $4.2\times 10^{-7}m$
(b) $2.7\times 10^{-6}m$
Work Step by Step
(a) We know that
$\Delta L=\frac{FL_{\circ}}{YA}$
We plug in the known values to obtain:
$\Delta L=\frac{(2400N)(sin25^{\circ})(0.02m)}{(1.6\times 10^{10}N/m^2)(0.003m^2)}$
$\Delta L=4.2\times 10^{-7}m$
(b) We know that
$\Delta L=\frac{FL_{\circ}}{YA}$
We plug in the known values to obtain:
$\Delta L=\frac{(2400N)(cos25^{\circ})(0.02m)}{(0.54\times 10^{10}N/m^2)(0.06m)(0.05m)}$
$\Delta L=2.7\times 10^{-6}m$
