Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 569: 70

Answer

Please see the work below.

Work Step by Step

We are given that the two objects absorb the same amount of heat, so $Q_1=Q_2$ $\implies m_1c_1\Delta T_1=m_2c_2\Delta T_2$ This equation can be rearranged as $\frac{\Delta T_1}{\Delta T_2}=\frac{m_2c_2}{m_1c_1}$. The above equation shows us that the temperature difference depends on the mass and specific heat and it doesn't depend on the coefficient of expansion or thermal conductivity.
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