Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 569: 58

Answer

$47^{\circ}C$

Work Step by Step

We can find the required temperature as follows: $T=T_1+(\frac{x}{L})(T_2-T_1)$ We plug in the known values to obtain: $T=21+(\frac{25}{81})(105-21)$ $T=47^{\circ}C$
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