Answer
$d=0.74m$
Work Step by Step
We can find the required depth as
$d=\frac{P_{at}/g-\rho_2(1.0m)}{\rho_{Hg}-\rho_w}$
We plug in the known values to obtain:
$d=\frac{\frac{1.01\times 10^5}{9.81}-(1000)(1.0)}{1.36\times 10^4-1000}$
$d=0.74m$