Answer
$1.12\frac{Kg}{m^3}$
Work Step by Step
We know that
$\rho_{hot\space air}=\rho_{air}-\frac{M}{V}$
We plug in the known values to obtain:
$\rho_{hot\space air}=1.29-\frac{1890}{11430}=1.12\frac{Kg}{m^3}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 532: 35
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