Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 530: 2

Answer

$W=0.93KN$

Work Step by Step

We know that $W=mg$ $\implies W=\rho Vg$ (where $m=\rho V$) We plug in the known values to obtain: $W=(1000)(25gal)(3.79\times 10^{-3}\frac{m^3}{gal})(9.81)$ $W=0.93KN$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.