Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 530: 8

Answer

$P=1.5\times 10^6Pa$

Work Step by Step

We know that $P=\frac{F}{A}$ $\implies P=\frac{mg}{4[\pi(\frac{d}{2})^2]}$ $P=\frac{mg}{\pi d^2}$ We plug in the known values to obtain: $P=\frac{(79+3.7)(9.81)}{\pi(0.013)^2}$ $P=1.5\times 10^6Pa$
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