Answer
(a) $7.9\frac{N}{m}$
(b) $4.6Kg$
Work Step by Step
(a) As know that
$T=2\pi \sqrt{\frac{m}{K}}$
This can be rearranged as:
$K=(\frac{2\pi}{T})^2m$
We plug in the known values to obtain:
$K=(\frac{2\pi}{1.5})^2(0.45)$
$K=7.9\frac{N}{m}$
(b) As $T=2\pi\sqrt{\frac{m}{K}}$
This can be rearranged as:
$m=(\frac{T}{2\pi})^2K$
We plug in the known values to obtain:
$m=(\frac{4.8}{2\pi})^2(7.9)$
$m=4.6Kg$
