Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 450: 89

(a) $0.112m$ (b) $0.142s$

(a) In the given scenario $K.E_i=U_f$ $\implies \frac{1}{2}mv^2=\frac{1}{2}KA^2$ This simplifies to: $A=\sqrt{\frac{mv^2}{K}}$ We plug in the known values to obtain: $A=\sqrt{\frac{(0.363)(1.24)^2}{44.5}}$ $A=0.112m$ (b) As $t=\frac{\pi}{2}\sqrt{\frac{m}{K}}$ $t=\frac{\pi}{2}\sqrt{\frac{0.363}{44.5}}$ $t=0.142s$