Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 372: 97

Answer

$2.0\times 10^3Kg$

Work Step by Step

We can find the mass of the tail as follows: $m_t=\frac{r_sm_s}{r_t+r_s}$ We plug in the known values to obtain: $m_t=\frac{(1.4m)(5400Kg)}{2.4m+1.4m}$ $m_t=2.0\times 10^3Kg$
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