Answer
$5.5mJ$
Work Step by Step
We can find the work done as
$W=\Delta K.E$
$\implies W=\frac{1}{2}I\omega^2$
$W=\frac{1}{2}(mr^2)(\frac{v}{r}^2)=\frac{1}{2}mv^2$
We plug in the known values to obtain:
$W=\frac{1}{2}(0.0065)(1.3)^2$
$W=5.5\times 10^{-3}J=5.5mJ$
