Answer
$0.054Kgm^2$
Work Step by Step
We can determine the required moment of inertia as follows:
$I=\frac{2K}{\omega^2}$
We plug in the known values to obtain:
$I=\frac{2(4.6J)}{(13rad/s)^2}$
$\implies I=0.054Kgm^2$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 326: 57
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
