Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 326: 42

(a) $v_t=68.8\frac{m}{s}$ (b) $T=7.31\times 10^{-5}s$

We know that $v_t=r\omega$ We plug in the known values to obtain: $v_t=(0.00320)(2.15\times 10^4)$ $v_t=68.8\frac{m}{s}$ (b) We also know that $T=\frac{2\pi r}{v_t}$ We plug in the known values to obtain: $T=\frac{2\pi(0.00320)}{275}$ $T=7.31\times 10^{-5}s$