Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems: 29

Answer

a. $9.06 \times 10^5 J$ b. $9.06 \times 10^5 J$ c. Yes.

Work Step by Step

a. Find the change in gravitational PE. $$\Delta PE = mgy_f-mgy_i=mg(y_f-y_i) = (66.5 kg)(9.80 \frac{m}{s^2})(1390 m)=9.06 \times 10^5 J$$ b. This is the minimum work required. c. The actual work is almost certainly greater than this because the hiker must overcome resistive forces and inefficiencies.
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