Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems: 17

Answer

$-5.51 \times 10^{-19} J$.

Work Step by Step

The work done on the electron is the change in its kinetic energy, by equation 6–4. The final KE is zero. $$W = \Delta KE = 0-\frac{1}{2} mv^{2}$$ $$W = -\frac{1}{2} (9.11 \times 10^{-31}kg)(1.10 \times 10^6 m/s)^{2}=-5.51 \times 10^{-19} J$$ The work is negative because the electron slows down.
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