Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - General Problems - Page 105: 69

Answer

$a = 0.86~m/s^2$

Work Step by Step

$ma = F_T ~sin(\theta)$ $mg = F_T ~cos(\theta)$ Let's divide the first equation by the second equation: $\frac{a}{g} = tan(\theta)$ $a = g ~tan(\theta) = (9.80 ~m/s^2)\cdot ~tan(5.0^{\circ})$ $a = 0.86~m/s^2$ The acceleration is $a = 0.86~m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.