Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 33 - Astrophysics and Cosmology - Problems - Page 981: 5

Answer

$2\times10^{-3}kg/m^3$

Work Step by Step

Density is mass divided by volume. $$\rho=\frac{M}{\frac{4}{3}\pi r^3}$$ $$ =\frac{1.99\times10^{30}kg}{\frac{4}{3}\pi (6\times10^{10}m)^3}$$ $$=2\times10^{-3}kg/m^3$$
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