Answer
$2.1\times10^8 ly$
Work Step by Step
Use equation 33–4, Hubble’s law.
$$v=H_od$$
$$d=\frac{v}{H_o}=\frac{(0.015)(3.00\times10^5km/s)}{21km/(s \cdot Mly)}=214Mly$$
$$=2.1\times10^8 ly $$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 33 - Astrophysics and Cosmology - Problems - Page 981: 23
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