Answer
0.009 MeV
Work Step by Step
Find the minimum uncertainty in the energy by using equation 28–2.
$$\Delta E \geq \frac{\hbar}{\Delta t}$$
$$=\frac{1.055\times 10^{-34}J \cdot s}{7\times10^{-20}s}\frac{1MeV}{1.60\times10^{-13}J}$$
$$ \approx 9\times10^{-3}MeV $$
