Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 32 - Elementary Particles - Problems - Page 945: 34

Answer

a. uss b. dss

Work Step by Step

a. The $\Xi^o$ baryon has a strangeness of -2, so it contains two strange quarks. It is a neutral particle. Therefore the third quark is an up quark. $$\Xi^o=uss$$ b. The $\Xi^-$ baryon has a strangeness of -2, so it contains two strange quarks. It has a charge of -1. Therefore the third quark is a down quark. $$\Xi^-=dss$$
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