Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 799: 27

Answer

3.32 eV

Work Step by Step

Use equation 27–5b to calculate the work function. $$ W_o =hf-KE_{max} =\frac{hc}{\lambda}-KE_{max}$$ The stopping potential of 1.64 volts tells us that the electrons have a maximum kinetic energy of 1.64 eV. In other words, the maximum KE is the product of stopping voltage and the magnitude of the electron’s charge. In this problem, the value of hc is useful. Use the result stated in Problem 29, $hc=1240\;eV \cdot nm$. $$ W_o=\frac{1240\;eV \cdot nm }{250nm}-1.64eV=3.32eV$$
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