Answer
$6.2\times10^4\frac{C}{kg}$
Work Step by Step
This is the experiment that is described by equation 27–1.
$$\frac{e}{m}=\frac{E}{B^2r}$$
$$=\frac{640V/m}{(0.86T)^2(0.014m)}=6.2\times10^4\frac{C}{kg}$$
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